3x^2+64=(2X^2)/2

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Solution for 3x^2+64=(2X^2)/2 equation: 


x in (-oo:+oo)

3*x^2+64 = (2*X^2)/2 // - (2*X^2)/2

3*x^2-((2*X^2)/2)+64 = 0

3*x^2-X^2+64 = 0

3*x^2 = -(64-X^2) // : 3

x^2 = (X^2-64)/3

x^2 = (X^2-64)/3 // ^ 1/2

abs(x) = ((X^2-64)^(1/2))/(3^(1/2))

x = ((X^2-64)^(1/2))/(3^(1/2)) or x = -(((X^2-64)^(1/2))/(3^(1/2)))

x in { ((X^2-64)^(1/2))/(3^(1/2)), -(((X^2-64)^(1/2))/(3^(1/2))) }

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